An airplane comes in for a landing with a velocity 66 m/s and travels 560 m while it comes to a stop Calculate the acceleration of the plane? (-3.9 m/s)
Proof please

a = -3.9m/s²

Explanation:

Given the following data;

Initial velocity = 66m/s

Displacement = 560m

To find the acceleration, we would use the third equation of motion

V² = U² + 2aS

Substituting into the equation we have

0² = 66² + 2*a*560

0 = 4356 + 1120a

-1120a = 4356

a = - 4356/1120

a = -3.9m/s²

explanation:

to push or pull an object in a certain direction is known as force. a force in moving an object from one place to another.

force depends on the mass of an object. so, more is the mass of an object more will be the force required to move the object.

thus, we can conclude that the use of force to move an object is push or pull.