You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizontal force of 900 N to make the top of the pole flex to the right. Y = 10.0 x 1010 N/m2 B = 9.0 x 1010 N/m2 S = 4.0 x 1010 N/m2
How far does the top of the pole flex to the right?

Explanation:

From the question we are told that

Height of circular cylinder is

Diameter of cylinder

Horizontal Force  

Generally the formula for shear modulus is mathematically represented by

Where

multiple

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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