A cube with a side length of 10cm is made up of aluminum metal (E= 25 x 10^9 N/m2) A horizontal shear force of 50000 N is applied to this cube. (a) How far will the top of the cube move in the horizontal directin relative to the bottom of the cube? (b) What is the shear stress appied to the cube? (c) Calculate the shear strain on the cube.​

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

pe = weightxheight = 2000x1000=2,000,000joules