The above stress can be approximated by a sinusoidal function (ie, sine wave) with an average 2,388 kPa, amplitude 293 kPa, and a frequency of 6 Hz. At a second flight condition, the stress had an additional sinusoidal component (ie, in addition to the first sine wave above) that has three times the above frequency, half of the magnitudes, and 90 degrees out of phase (leading). Determine the amplitude of the second sinusoidal component in kPa. Provide the answer using 2 decir placed.

Where is the table ? you can take a picture of it

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.