Car A is stopped at a traffic light. At the moment it starts to move again, it is situated 330 m from car B, which is traveling in the opposite direction at a constant velocity of 18.0 m/s. If car A accelerates at a rate of 3.0 m/s^2, where and after how long will the two cars pass each other?​
Please answer this question with steps..​

hopr

Explanation:

Let t be the time it takes for the car to catch up with the truck. Using kinematics equations, Distance by car = ut + 0.5at² = 0 + 0.5 * 3.72 * t². Distance by truck = 13.8 * t. Since these distances have to be equal, we have: 0.5 * 3.72 * t² = 13.8t, 1.86t² = 13.8t, t ≈ 7.42s. Hence, the distance is 13.8 * (7.42) ≈ 102.4m.

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.

there are no components of a physical goal mentioned on the list of choices that you've provided.