The train accelerates from 30 km/h to 45 km/h in 15 secs. a. find its acceleration. b. distance it travels during this time

Answer :

(a) The acceleration is,

(b) Distance it travels during this time is, 156.225 m

Solution for part (a) :

Formula used :

where,

a = acceleration

v = final velocity =

u = initial velocity =

t = time = 15 s

Now put all the given values in the above formula, we get

Therefore, the acceleration is,

Solution for part (b) :

Formula used :

where,

s = distance traveled

Now put all the given values in this formula, we get

Therefore, the distance it travels during this time is, 156.225 m

0.863333

86%

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