An archer shoots an arrow 75 m distant target; the bull's-eye of the target is at the same height as the release height of the arrow. If d = 75 m and v = 37 m/s. At what angle must the arrow be released to hit the bull's-eye if its initial speed is 37 m/s?

Explanation:

R = Horizontal range of projectile = 75 m

v = Velocity of projectile = 37 m/s

g = Acceleration due to gravity =

Horizontal range is given by

The angle at which the arrow is to be released is .

number of electrons for neutral cl

answer: 31, 5556. 952 seconds