Physics, 29.08.2019 09:00 highflylex279

9)
maximum height of rockets
half-filled three-quarters filled full
2-liter bottle 18m 21m 17m
1-liter bottle 12m 15m 20m
0.5-liter bottle 10m 12m 14m
plastic soda bottles are hooked up to a launcher. the launcher uses the water pressure to propel the rocket upward. what combination yields greatest height?
a) a full 2-liter bottle
b) a full 1-liter bottle.
c) a three-quarter full 1-liter bottle
d) a three-quarter full 2-liter bottle

Answers: 2

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Answers

The plastic soda bottles should be
D) A three-quarter full 2-liter bottleThe bottle with the greater volume will create more pressure but that pressure is delivered through the gas that is in the space in the bottle that is why the bottle should not be completely full.

Answer from: sairaanwar67

Hello there.

Maximum height of rockets

Half-filled Three-quarters filled Full
2-liter bottle 18m 21m 17m
1-liter bottle 12m 15m 20m
0.5-liter bottle 10m 12m 14m

Plastic soda bottles are hooked up to a launcher. The launcher uses the water pressure to propel the rocket upward. What combination yields greatest height?

Option D
( D) A three-quarter full 2-liter bottle

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

Answer from: Quest

Answerigneous bedrock of the oceanic crust;

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9)
maximum height of rockets
half-filled three-quarters filled full
2-liter bottl...

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