subject
Physics, 31.01.2020 19:01 Jonny13Diaz

Can someone me ? i need to finish this because i have more homework and i need to go to bed


Can someone me ? i need to finish this because i have more homework and i need to go to bed<

ansver
Answers: 2

Another question on Physics

question
Physics, 22.06.2019 10:50
Asubject in a clinical research trial experiences a serious, unanticipated adverse drug experience. how should the investigator proceed, with respect to the irb, after the discovery of the adverse event occurrence? a. do not report the adverse drug experience to the irb since it is a common adverse experience.b. report the adverse drug experience to the irb only if there are several other occurrences.c. report the adverse drug experience as part of the continuing review report.d. report the adverse drug experience in a timely manner, in keeping with the irb's policies and procedures, using the forms or the mechanism provided by the irb.
Answers: 1
question
Physics, 22.06.2019 22:00
Which statement best explains why the overall charge on an atom is zero?
Answers: 1
question
Physics, 23.06.2019 00:20
What efficiency of a car's engine when heat input is 200,000 joules and waste heat is 150,000 joules? a. 75% b. 35% c. 25% d. 85%
Answers: 2
question
Physics, 23.06.2019 01:30
Amerry-go-round of radius r, shown in the figure, is rotating at constant angular speed. the friction in its bearings is so small that it can be ignored. a sandbag of mass m is dropped onto the merry-go-round, at a position designated by r. the sandbag does not slip or roll upon contact with the merry-go-round. how would you rank the following different combinations of m and r on the basis of the angular speed of the merry-go-round after the sandbag "sticks" to the merry-go-round from largest to smallest. a) m = 10kg, r = 0.25r b) m = 20kg, r = 0.25r c) m = 10kg, r = 0.50r d) m = 10kg, r = 1.0r e) m = 15kg, r = 0.75r f) m = 40kg, r = 0.25r
Answers: 1
You know the right answer?
Can someone me ? i need to finish this because i have more homework and i need to go to bed
...
Questions
Questions on the website: 13722367