A110 n force and a 55 n force both act on an object point p. the 110 n force acts at 90 degrees. the 55 n force acts at 0 degrees. what is the magnitude and direction of the resultant force?

To determine the magnitude and the direction of the resultant force, we assume that the forces are in XY coordinate plane and the angles that are given are from  the x axis.
 
The 110 N force is said to act at 90 deg which means it is along the Y axis. The 55 N force is said to act at 0 deg which means it is along the X axis. so, a right angle is made by the two forces. Thus, the

X component of the resultant force = 55 N 
Y component of the resultant force = 110 N 
Magnitude of the resultant force would be calculated as follows:
R = √(Fx^2 + Fy^2)
R = √(55^2 + 110^2)  
R = √(15125) 
R = 123 N 
The resultant force  would have its terminal side in the x-axis. We calculate angle θ as follows:
 
tan θ = Fy/Fx 
tan θ = 110 N /55 N = 2
θ = arctan(2) 
θ = 63.4 degrees
Therefore, the magnitude of the resultant force is 123 N and the direction would be at an angle of 63.4 degrees.

10 neutrons is the answer