If the radius of the equipotential surface of the point charge is 14.3 m at a potential of 2.20 kV, what will be the magnitude of the point charge that generates the potential?

The magnitude of the point charge is 3.496 x 10⁻⁶ C

Explanation:

Given;

radius of the surface, r = 14.3 m

magnitude of the potential, V = 2.2 kV = 2,200 V

The magnitude of the point charge is calculated as follows;

Therefore, the magnitude of the point charge is 3.496 μC

gravity

explanation:

we need to know the time interval during which the force acts. impulse of force = momentum change