A baseball is thrown vertically upward with an initial velocity of 20m/s. A, what maximum height will it attain? B, what time will elapse before it strike the ground?
C, what is the velocity just before it strike the ground?​

Look at explanation

Explanation:

a)Only force acting on the object is gravity, so a=-g (consider up to be positive)

use: v^2=v0^2+2a(y-y0)

plug in givens, at max height v=0

0=400-19.6(H)

Solve for H

H= 20.41m

b) Use: y=y0+v0t+1/2at^2

Plug in givens

0=0+20t-4.9t^2

solve for t

t=4.08 seconds

c) v=v0+at

v=20-39.984= -19.984m/s

the answer is d. 4

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