A ball of mass 1.0 kg is rolling due west at 30 m/s. A second ball of mass 2.0 kg moving due north at 6.0 m/s collides with the first ball and they stick together. What is the magnitude of the momentum of the two-ball system immediately after collision

the magnitude of the momentum of the two-ball system immediately after collision is 32.31 kg.m/s

Explanation:

Given;

mass of the first ball, m₁ = 1.0 kg

mass of the second ball, m₂ = 2.0 kg

initial velocity of the first ball, v₁ = 30 m/s due west

initial velocity of the second ball, v₂ = 6 m/s due north

From the principle of conservation of linear momentum;

the total momentum before collision = total momentum after collision

The westward momentum of the first ball, = m₁v₁ = 1 x 30 = 30 kg.m/s

The northward momentum of the second ball = m₂v₂ = 2 x 6 = 12 kg.m/s

The resultant momentum of the two balls;

R² = 30² + 12²

R² = 1044

R = √1044

R = 32.31 kg.m/s

Therefore, the magnitude of the momentum of the two-ball system immediately after collision is 32.31 kg.m/s

(75°f − 32) × 5/9 = 23.889°c

i believe the answer would be:

d. violin, clarinet, french horn, and tuba