19 point please please answer right need help Block on an incline
A block of mass m1 = 3.9 kg on a smooth inclined plane of angle 38is connected by a cord over a small frictionless
pulley to a second block of mass m2 = 2.6 kg hanging vertically. Take the positive direction up the incline and use 9.81
m/s2 for g.
What is the tension in the cord to the nearest whole number?

Explanation:

We can write Newton's 2nd law as applied to the sliding mass as

For the hanging mass we can write NSL as

We need to solve for a first before we can solve the tension T. So combining Eqns(1) & (2), we get

or

Using this value for the acceleration on Eqn(2), we find that the tension T is

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.