A 1.99 kg particle has the xy coordinates (-1.93 m, 0.399 m), and a 5.39 kg particle has the xy coordinates (0.993 m, -0.719 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 4.09 kg particle such that the center of mass of the three-particle system has the coordinates (-0.691 m, -0.993 m)

the motion of a pendulum is a classic example of mechanical energy conservation. a pendulum consists of a mass (known as a bob ) attached by a string to a pivot point. as the pendulum moves it sweeps out a circular arc, moving back and forth in a periodic fashion.

its c i just checked it

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west