Una persona suelta una piedra desde una azotea de 45 m de altura. Calcular: a) ¿con qué velocidad llegará la piedra al suelo? , b) ¿cuánto tiempo tardará en llegar al
suelo?

v ≈ 29.69 m/s ,t ≈ 3.02s

Explanation:

a) ¿con qué velocidad llegará la piedra al suelo?

v^2=u^2+2as

v^2=0^2+2*9.8*45

v^2=882

v ≈ 29.69m/s

b) ¿cuánto tiempo tardará en llegar al suelo?

s=ut+1/2at^2

45=0*t+1/2(9.8)t^2

45=4.9t^2

45/4.9=t^2

t^2 ≈ 9.18

t ≈ 3.02s

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