PLEASE HELP BRAINLIEST TO THE RIGHT ANSWER The coefficient of static friction between a car of mass 1500kg and the road is 0.7. What is the distance over which the car will come to a stop from 42 m/s, if the car is only slowing down because of friction?

Explanation:

Answer in the figure Hope it helps you

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.