Asample of ch4o with a mass of 32.0 g contains how many molecules of ch4o?

According to Avagadro's constant 1 mole of a substance contains 6.022× 10^23 particles (molecules, atoms or ions).
1 mole  of CH4O contains 32 g
therefore; 32 g of CH4O is equivalent to 1 mole;
Hence; 32 grams of CH4O contains 6.022 ×10^23 molecules.

Only one reactant yields 2 or more products. meaning you will only have 1 product and it will break down into 2 or more products. eg. h2o -> h2 + o2