Potassium chlorate (kclo3) decomposes into potassium chloride (kcl) and oxygen gas (o2) how many grams of oxygen can be produced from the decomposition of 7.38 moles of potassium chlorate

Consider this reaction  : 2KClO3 → 2KCl + 3O2  

Mole ratio = 3(O2) : 2(KClO3)

Number of moles of O2 = 3/2*7.38 = 11.07 mol

Number of moles of 02 = mass/molar mass

Therefore, mass = 11.07*(16*2) = 354.24 g

Note: It's mandatory to always balance the reaction at first

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