If you used 61.5mL of 3.80 M KOH to titrate 15.0 ML of H2SO4, what was the concentration of the H2SO4?.

15.58 was the concentration of the H2SO4 used.

Explanation:

In titration the concentration of unknown solution can be known from the formula:

Macid x V acid = Mbase x Vbase        equation 1

data given:

volume of base i.e KOH = 61.5 ml

molarity of base = 3.80 M

Volume of the acid H2SO4 = 15 ml

molarity of the acid = ?

Applying the formula:

Macid x V acid = Mbase x Vbase

M acid x 15 = 61.5 x 3.8

x =  

   = 15.58

Molarity of H2SO4 used is 15.58 M

Concentration of H₂SO₄ is 7.79 M

Explanation:

Neutralization of KOH by sulfuric acid is given by the equation as,

2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

1/2 mole of KOH is needed to neutralize 1 mol of sulfuric acid.

V1 = volume of KOH and M1 = molarity of KOH

V2 = Volume of  H₂SO₄ and M2 = molarity of H₂SO₄

Here we can write the equation of volumetric analysis as,

V1M1 = 2V2M2

M2 =

   =

 = 7.79 M

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