Na2SO4(aq) +CaCl2(aq). CaSO4(s) + 2NaCl(aq) Ionic Equation:
2Na+ (aq) + SO2 (aq) + Ca2+ (aq) + 2C1- (aq) –
CaSO4(s) + 2Na+(aq) + 2C1- (aq)
Recall that spectator ions are ions present in
solution that do not participate directly in the
reaction. What are the spectator ions in this
reaction?
A. Ca2+ and SO2 B. Na+ and SO
C. Na+ and CI D. Ca2+ and CI-

Na2SO4(aq) +CaCl2(aq). CaSO4(s) + 2NaCl(aq) Ionic Equation: 2Na+ (aq) + SO2 (aq) + Ca2+ (aq) + 2C1- (aq) – CaSO4(s) + 2Na+(aq) + 2C1- (aq) Recall that spectator ions are ions present in solution that do not participate directly in the reaction. What are the spectator ions in this reaction? A. Ca2+ and SO2 B. Na+ and SO C. Na+ and CI D. Ca2.

Explanation:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.