21) Base your answer on the information below and on your knowledge of chemistry.
A hydrate is a compound that has water molecules within its crystal structure.
Magnesium sulfate heptahydrate, MgSO4.7H20, is a hydrated form of magnesium
sulfate. The hydrated compound has 7 moles of H2O for each mole of MgSO4. When
5.06 grams of MgSO4.7H20 are heated to at least 300.°C in a crucible by using a
laboratory burner, the water molecules are released. The sample was heated
repeatedly, until the remaining MgSO4 had a constant mass of 2.47 grams. During
this laboratory activity, appropriate safety equipment was used and safety
procedures were followed.
Determine the gram-formula mass of the anhydrous magnesium sulfate and the gfm for the
hydrate?

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

the objects have the same charge.

4d^55s^1 ( third choice)