Given the assembly instruction: bne $s0, $s1, done the address of the instruction is 500bytes. if the offset field contains the following value: 01002, what is the target address? explain your answer.

The target audience is 492

Explanation:

From the given formula

target audience = pc address + offset field value

And pc address = 500 + 04 = 504

The offset field value when converted to decimal, gives the value of -12

i.e 11111111111101002 = -12 in decimal

Hence the target audience = 504 + (-12)

= 492

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explanation:

answerthe above statement is (false);