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Anybody wanna join my clash of clans clan?

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Computers and Technology, 23.06.2019 01:00
Petrică, tânăr licean în clasa a ix-a, a primit în dar de la părinţii săi un cont bancar pentru micile sale cheltuieli curente. el este pasionat de internet banking şi îşi verifică cu grijă toate tranzacţiile efectuate. pentru creşterea securităţii tranzacţiilor online, banca îi furnizează lui petrică un număr pe care el va trebui să îl modifice, obţinând un număr tan – număr de autentificare a tranzacţiei (transaction authentication number). regula de obţinere a numărului tan este următoarea: se formează cel mai mic număr par din toate cifrele numărului furnizat de bancă. cerinţă cunoscând numărul n furnizat de bancă, să se determine numărul tan obţinut de petrică. date de intrare fişierul tan.in conţine pe prima linie numărul natural n cu semnificaţia din enunţ. date de ieşire fişierul de ieşire tan.out va conţine o singură linie pe care va fi scris numărul tan cerut. restricţii • 0 < n < 18*1018 • n are cel puţin o cifră pară • numărul tan obţinut nu poate conţine zerouri nesemnificative
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Computers and Technology, 23.06.2019 02:50
Define a class named movie. include private fields for the title,year, and name of the director. include three public functions withprototypes void movie: : settitle(cstring); , voidmovie: : setyear(int); , void movie: : setdirector(string); . includeanother function that displays all the information about a movie.write a main() function that declares a movie object namedmyfavoritemovie. set and display the object's fields.this is what i have but know its wrong since it will notcompile: #include#includeusing namespace std; //class declarationclass movie{private: string movietitle ; string movieyear; string directorname; public: void settitle(string title); void setyear(string year); void setdirector(string director); void displayinfo(); }; //class implementationvoid movie: : settitle(string title){ movietitle = title; cout< < "what is the title of themovie? "< > temp; myfavoritemovie.settitle(temp); cout< < "enter movie year"< > temp; myfavoritemovie.setyear(temp); cout< < "enter director'sname"< > temp; myfavoritemovie.setdirector(temp); //display all the data myfavoritemovie.displayinfo(); system("pause"); return 0; this code is not entirely mine someone on cramster edited my firstcode but then i try manipulating the new code and i still get acompile error message : \documents\visual studio 2008\projects\movie\movie\movie.cpp(46) : error c2679: binary '< < ' : no operator found which takes aright-hand operand of type 'std: : string' (or there is no acceptableconversion)c: \program files (x86)\microsoft visual studio9.0\vc\include\ostream(653): could be'std: : basic_ostream< _elem,_traits> & std: : operator< < > (std: : basic_ostream< _elem,_traits> & ,const char *)w
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Computers and Technology, 23.06.2019 09:30
Which of the following tasks is an audio technician most likely to perform while working on a nature documentary? (select all that apply). eliminating potentially distracting background noise adding sound effects making sure the lighting is adequate for a particular scene changing the narration to better match the mood of the documentary
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Computers and Technology, 23.06.2019 17:30
When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?
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