Abox p contains 3 white and 4 green balls. another box q contains 5 white and 2 green balls. a ball is drawn at random from box p and dropped into box q. a ball is then drawn at random from box q. find the probability that the ball drawn from box q is white.

For the first part of experiment, we have two outcomes,

A = white ball with probability 3/7

We then have 6 white and 2 non-white balls.

P(W)=3/7*6/8=9/28

B= non-white ball with probability 4/7

We then have 5 white and 3 non-white balls

P(W)=4/7*5/8 = 5/14

Total probability of picking a white ball in the second step = 9/28+5/14=19/28

p: 3 white 4 green → white drawn: 3 out of 7 ()

→ green drawn: 4 out of 7 ()

q: 5 white 2 green → white drawn from p: 6 out of 8 ()

→ green drawn from p: 5 out of 8 ()

Probability of white from p and white from q:

x =

Probability of green from p and white from q:

x =

white p & white q or green p & white q

or

or = [tex] \frac{19}{28}

[tex] \frac{19}{28}

-3.396 = -3.4

-0.708 = -0.7

0.304 = 0.3

0.955 = 1

he is going to fill two shelves and the third shelf will only have five video games