Aball is thrown vertically upward. after t seconds, its height h (in feet) is given by the function h(t) = 60t - 16t^2 . what is the maximum height that the ball will reach?
do not round your answer.

56.25 feet.

Step-by-step explanation:

For a Quadratic function in the form , if then the parabola opens downward.

Rewriting the given function as:

You can identify that

Since then the parabola opens downward.

Therefore, we need to find the vertex.

Find the x-coordinate of the vertex with this formula:

Substitute values:

Substitute the value of "t" into the function to find the height in feet that the ball will reach. Then:

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2

i believe a. 12x≥120 is the answer