If there is a 50% chance that it will rain today and a 50% chance that it will rain tomorrow, what is the probability that it rains at least one of the days?

0.75

Step-by-step explanation:

Given that there is a 50% chance that it will rain today and a 50% chance that it will rain tomorrow

We find that these two events are independent

A = rains today and B = rains tomorrow

A and B are independent

So we have

P(AB) =P(A)P(B)

the probability that it rains at least one of the days

= P(A or B) =P(A)+P(B)-P(AB)

=0.5+0.5-0.5(0.5)

=0.75

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.