The system of equation, if a b are arbitrary numbers x+2y-3z- a 2x+4y-6z 2a+2 has (a) no solutions regardless of values of a and b (b) infinitely many solutions regardless of values of a and b (c) a unique solution if a b-0 d) a unique solution regardless of values of a and b

(A) No solutions regardless of values of a and b.

Step-by-step explanation:

Asumming that the system of equations is , the corresponding augmented matrix of the system is .

If two time the row 1 is subtracted to row 1, we get the following matrix

.

Then the system has no solutions regardless of values of a and b.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)