The equation 2x2 − 12x + 1 = 0 is being rewritten in vertex form.
Fill in the missing step.
Given 2x2 − 12x + 1 = 0
Step 1 2(x2 − 6x ___) + 1 ___ = 0
Step 2 2(x2 − 6x + 9) + 1 − 18 = 0
Step 3 ✔

2(x − 3)2 + 17 = 0

2(x − 3)2 − 17 = 0

2(x + 3)2 − 17 = 0

2(x − 6)2 − 17 = 0

Given ⇒ 2x² - 12x + 1 = 0

Step 1 ⇒ 2(x² - 6x + 3²) + 1 - 2(3²) = 0

Step 2 ⇒ 2(x² - 6x + 9) + 1 - 18 = 0

Step 3 ⇒ 2(x - 3)² - 17 = 0

The steps are

Separate the first two terms from the constant

Divide the coefficient of the x-term by 2, square the result, and add that inside the parenthesis to complete the square.

Since you added inside the parenthesis, you will need to subtract outside the parenthesis to keep the equation balanced.

Factor the trinomial inside the parenthesis and simplify the constant terms outside the parenthesis.

Do these steps to get B 2(x − 3)2 − 17 = 0

Step-by-step explanation:

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