The number of people who use the ATM at night outside your local bank branch can be modeled as a Poisson distribution. On average 1.2 customers arrive every hour (late at night). You park outside the bank to count the customers. What is the probability that in the hour between 10 and 11 PM at least one customer arrives?

0.6988

Step-by-step explanation:

Given that the number of people who use the ATM at night outside your local bank branch can be modeled as a Poisson distribution.

Let X be the number of customers arriving between 10 and 11 am.

X is Poisson with mean= 1.2

Required probability

=  the probability that in the hour between 10 and 11 PM at least one customer arrives

= P(X≥1)

=1-P(X=0)

=1-0.3012

= 0.6988

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

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step-by-step explanation:

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