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Solving for X in a Right Triangle

Add 90 degrees for the right angle to the degree measurement of the other marked angle. This measurement will be found inside the triangle at the angle that is not denoted by the X variable.

Subtract the sum of the two angles from 180 degrees. The sum of all the angles of a triangle always equals 180 degrees.

Write down the difference you found when subtracting the sum of the two angles from 180 degrees. This is the value of X.

Solving for X in an Isosceles Triangle

Locate the two base angles that are marked with half-circles with lines through them. These two angles are the same size.

Multiply the measurement given for one of the angles by two, if these angles have a measurement given. In this case you are solving for X at the vertex. Subtract the doubled measurement of the angles from 180. This is the value of the X angle at the vertex.

Subtract the measurement of the vertex angle from 180, if you are only given the measurement of the vertex angle. Divide the difference of the subtraction by two. This will give you the value of X at either of the base angles.

Solving for X in Other Triangles

Add the given degrees of the two angles provided and subtract that from 180 to solve for X in obtuse and acute triangles.

Compare the result with the visual representation of the triangle. With obtuse triangles, one angle will be larger than 90 degrees. If you are solving for this angle, be sure the figure you obtain for X is larger than 90 degrees. Acute triangles all have angles smaller than 90 degrees. Be sure that X is smaller than 90 degrees when solving for an acute triangle.

Determine if the triangle is equilateral by observing the half-circles drawn around all three of the angles with single lines drawn through all of them. If you are dealing with an equilateral triangle, all the angles equal 60 degrees and no additional mathematics is needed to determine the measurements.

Step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c