What are the values of a, b, and c in the quadratic equation 0 = x - 3x – 2?
O : 36 = 3, c= 2
0 8 = 7 / 0 = -3, c= -2
O = 3,0 = 3,C= -2
O a = b = -3,c=2

The values of a,b and c are 1, -3 and -2 respectively.

Step-by-step explanation:

The general form of quadratic equation is given by :

.....(1)

Here, a,b and c are constants

The given equation is :

We can also write the above equation as :

....(2)

If we compare equation (1) and (2), we get :

a = 1

b = -3 and

c = -2

So, the values of a,b and c are 1, -3 and -2 respectively.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

part a: 1.08

part b: 27.59