Robin is a competitive archer. Her average arrow is within 6.5 cm of the center of the bullseye. John, Robin's trainer, keeps close records of each of Robin's shots so he can tell if she is improving. The graph below is John's record of Robin's last three arrows, where (0,0) is the center of the bullseye.

Arrow C.

Step-by-step explanation:

Out of three arrows, nearest arrow from the origin will be the best arrow.

Ordered pair for arrow A → (-5, 4)

Distance between A and bullseye =

                                                    =  

                                                    =

                                                    = 6.40 units

Ordered pair for arrow B → (5, -5)

Distance between B and bullseye =

                                                         =

                                                         = 7.1 units

Ordered pair for arrow C → (-2, -6)

Distance between C and the bullseye =

                                                               =

                                                               = 6.32 units

Distance between C and the bullseye is the shortest.

Therefore, arrow C will be the best arrow.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1