if two polynomial equations have real solutions , then will the equation that is the result of adding , subtracting or multiplying the two polynomial equation also have real solutions

multiplying is the right answer

Step-by-step explanation:

multiplying is not a problem, multiplying the two polynomial equations also has real solutions

adding or substracting does not work though

(1) has two real solutions

(2) has two real solutions

but (1) - (2) gives

= 0

this one has no real solution

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2