In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arrested previously for a DUI offence. Suppose 41 people arrested for DUI in Illinois are selected at random. You may assume that this is a binomial distribution. Required:
a. What is the probability that exactly 3 people are repeat offenders?
b. What is the probability that at least one person is a repeat offender?
c. What is the mean number of repeat offenders?
d. What is the standard deviation of the number of repeat offenders?

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

The expected value of the binomial distribution is:

The standard deviation of the binomial distribution is:

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that

41 people arrested for DUI in Illinois are selected at random.

This means that

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

We want .

Then

In which

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

d. What is the standard deviation of the number of repeat offenders?

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

acd, jgvjgbgbgvhgbhjjn