A cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. A cylinder has a height of 20 centimeters and a diameter of 8 centimeters. What is the approximate volume of the tube? Round to the nearest whole cubic centimeter. 1,005 cm3 1,340 cm3 3,351 cm3 4,021 cm3

4021 cm^3

Step-by-step explanation:

The volume of a cylinder can be found using the following formula.

where r is the radius and h is the height.

We know the cylinder has a height of 20 centimeters and a diameter of 8 centimeters.

h= 20 cm

d= 8 cm

Substitute these values into the formula.

First, evaluate the exponent.

8 cm^2= 8 cm * 8 cm= 64 cm

Multiply 64 cm^2 and 20 cm

Multiply 1280 cm^3 and pi

Round to the nearest cubic centimeter. The 2 in the tenth place tells us to leave the number as is.

The volume is about 4,021 centimeters^3.

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

what does x eaqual

step-by-step explanation: