URGENT It is given that a regular n-sided polygon has 5 sides more than a regular m-sided polygon. If the sum of interior angles of the regular
n-sided polygon is twice that of the latter, find the values of m and n.

m = 7; n = 12

Step-by-step explanation:

"a regular n-sided polygon has 5 sides more than a

regular m-sided polygon"

n = m + 5

The sum of the measures of the interior angles is

180(n - 2) for the n-sided polygon and

180(m  2) for the m-sided polygon.

"If the sum of interior angles of the regular

n-sided polygon is twice that of the latter"

180(n - 2) = 2(180)(m - 2)

We have a system of equations with 2 equations.

n = m + 5

180(n - 2) = 2(180)(m - 2)

Simplify the second equation:

n - 2 = 2m - 4

n + 2 = 2m

Substitute m + 5 for n.

m + 5 + 2 = 2m

7 = m

m = 7

n = m + 5 = 7 + 5 = 12

m = 7; n = 12

doubled

step-by-step explanation: