The $x$-intercept of a positively-sloped line is -5, and the area of the triangle formed by the line, the $x$-axis, and the $y$-axis is 10. What is the slope of the line?

4/5 OR -4/5

Step-by-step explanation:

So, area of triangle = 1/2 * base * height

base = 5 (because x-axis is base, x-intercept is -5, so x-length = 5)

height is unknown

area = 10

We can form the equation: 1/2 * 5 * height = 10

Rearrange terms to get: height (y-height) = 10 / (0.5 * 5) = 4

Following the formula for gradient, dif in y / dif in x, we get 4/5

Therefore our gradient is (4/5), or 0.8.

But because we are only told the x-intercept, it can cross the y axis at y = 4 or y = -4. So there are actually 2 possible gradients, 4/5 and -4/5

neither i nor ii 56 / 4.9 = 11.91489362 and 82 / (11+5) =5.125 so i is wrong

ii. (24/8+2) times 3 = 15 and (42+9)/2 =25.5

step-by-step explanation:

56

do you have the measurements?