If anyone knows how to do this stuff I would love some help (✿◠‿◠)

See explanation below

Step-by-step explanation:

(a) The spread of the data is represented by their range,

Adam's Range : 106 - 91 = 15

Miguel's Range : 105 - 86 = 19

As Miguel's Range is greater, his data has the greater spread

(b) The middle 50 percent of both data sets would be the following,

Adam | 103 | 105 | 104 | 106 | 100

Miguel | 88 | 86 | 89 | 93 | 105

And their 50% range would be ...

Adam's 50% Range : 106 - 100 = 6,

Miguel's 50% Range : 105 - 86 = 19

Adam still has the least spread, even in the middle 50%

(c) This proves that their is a small variance in Adam's training times, but a large variance in Miguel's training times (Miguel's data is more likely skewed).

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )