what is a equation of the line that passes through the point (-4,-6) and is parallel to the line 3x-y=6

Step-by-step explanation:

When solving these types of problems you need to know how to write a line that is parallel to another line. Parallel lines have the same SLOPE but different y-intercepts. But in order to do this, we need to convert this equation to slope-intercept form: y=mx+b.

First, we want to get -y by itself therefore we want to subtract 3x on both sides to get  . We then want to isolate y by dividing by -1 on each side to get the new equation  . We can then use this equation to make a line that is parallel.

Utilizing the slope from the original equation (3) and using the same format for slope-intercept, we get . Our line goes through a certain point therefore our x and y values are given so that our equation looks like . We now simplify to get and add 12 on both sides to get b by itself .

Lastly, we have all our values and now just need the equation for the line which leaves us with .

If you don't understand something or need more help, feel free to ask.  

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

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