MNO and MPO are isosceles triangles. Find angle t

t = 20°

Step-by-step explanation:

Recall that the base angles of an isosceles ∆ are equal to each other.

This means that:

<NMO and <NOM of ∆MNO are congruent to each other.

Thus,

m<NMO = ½(180 - m<N) = ½(180 - 70)

m<NMO = ½(110)

m<NMO = 55°

Also, <PMO and <POM are congruent to each other. Thus:

m<PMO = ½(180 - m<P) = ½(180 - 110)

m<PMO = ½(70)

m<PMO = 35°

Therefore,

m<NMO = t + m<PMO (angle addition postulate)

55° = t + 35° (substitution)

Subtract 35 from each side

55° - 35° = t

20° = t

t = 20°

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step-by-step explanation:

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x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)