Find the equation of a line that passes through the point (-2,3) and has a gradient of 3. Leave your answer in the form y = mx + c

y = 3x+9

Step-by-step explanation:

The standard form of equation of a line is in the form y = mx + c

m is the gradient

c is the y intercept

Get the y-intercept

Substitute m = 3 and the point (-2, 3) into the formula y = mx+c

3 = 3(-2) + c

3 = -6+c

c = 3+6

c = 9

Get the required equation;

y = 3x + 9

Hence the required equation is y = 3x+9

the answer is b.

64

step-by-step explanation:

c=2πr=2·π·8≈64

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