find the area and perimiter of the figure, given that AB is a semi-circle that has the length 24 π cm

Perimeter ≈ 61.68, Area ≈ 226.08

Step-by-step explanation:

The original equations for a regular circle are as follows:

Circumference = 2πr

Area = πr^2

With these in mind, let us continue. We must first find the Circumference and Area of a circle with this radius. To do this we plug in the radius which we can derive from taking the length of the semi-circle. Dividing 24/2 will give us 12 which is the radius. Evaluating both equations with r = 12 and π = 3.14 will give us Area = 452.16 and Circumference = 75.36. Great, we now have the values we need. However, this is for a full circle, and we are trying to solve for a semi-circle. To resolve this, all we have to do is divide the Area by 2 and that will give us half of that circle (the semi-circle). For the Circumference, we divide by 2 as well, but we also must add the diameter which is 24 giving us 226.08, and 61.68 respectively.

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.