I need help ASAP PLEASE

g has an average rate of change of zero at the intervals [-5,4] and [-2,2]

Step-by-step explanation:

When we talk of the average rate of change, we mean the change in y values divided by the change in x values

Once the change in y-values is zero, then over that interval, the average rate of change is zero

at the point t =- 5, g(t) = 6; at the point t = 4, g(t) = 6

As we can see here, within the interval [-5,4]; the average rate of change is 0

This same pattern is repetitive at points or ranges where we have same values for g(t)

such as;

[-2,2]

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

a

step-by-step explanation: