Complete the general form of the equation of a sinusoidal function having an amplitude of 1, a period of pi/2, and a vertical shift up 3 units. y = (i don't have the option to use the characters "/" or "" so they must not be in the answer.

y = sin 4x + 3

Step-by-step explanation:

A sine function is represented as y = a sin(bx + c) + d

Given values in the question are a = amplitude = 1

period = π/2 = 2π/b

Vertical shift d = 3 units up.

Horizontal shift c = 0

Since 2π/b = π/2

Now the sinusoidal function will be

y = 1. sin( 4x ) + 3

y = sin 4x + 3

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3