7x - 3y = 4 2x - 4y = 1 which of the following system of equations is not equal to the system of equations shown above? a.28x - 12y = 16 and -6x + 12y = -3 b.14x - 6y = 4 and -14x + 28y = 1 c.-28x + 12y = -16 and 28x - 56y = 14

Option B

Step-by-step explanation:

The given equations are 7x - 3y = 4 (1) and 2x - 4y = 1 (2)

Option A : we multiply equation (1) by 4 then

28x - 12y = 16 (3)

We multiply equation (2) by (-3) then we get.

-6x + 12y = -3 (4)

Equation 3 and 4 are similar as 1 and 2 .

Therefore, option A is correct represent similar equations.

Option B : By multiplication equation (1) by 2

14x - 6y = 8

and multiplication equation (2) by (-7)

-14x + 28y = (-7) (Therefore, equations does not match the system of equation)

Option C : If we multiply equation (1) by (-4)

-28x + 12y = -16

and multiply equation (2) by 14 we get.

28x - 56y = 14

These equations are similar to system of equations.

Therefore, Option B is the answer.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

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