A50-cm-long spring is suspended from the ceiling. a 290 g mass is connected to the end and held at rest with the spring unstretched. the mass is released and falls, stretching the spring by 30 cm before coming to rest at its lowest point. it then continues to oscillate vertically.
(a) what is the spring constant? (k=)
(b) what is the amplitude of the oscillation?
(c) what is the frequency of the oscillation?

a) Spring Constant

b) Amplitude of the oscillation

c)Frequency o the oscillation

Explanation:

Given:

a)

When Finally the mass comes to rest after 30 cm of stretching in spring then work done by all the forces is equal to the change in kinetic Energy of the of the mass

b) The Amplitude of the oscillation is 0.3 m

c) Let Frequency of the oscillation of the mass be which is given by

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2