Apassenger walks from one side of a ferry to the other as it approaches a dock. passenger's velocity is 1.55 m/s due north relative to the ferry, and 4.50 m/s at an angle of 30.0° west of north relative to the water. (a)what is the magnitude of the ferry's velocity relative to the water? (b) what is the direction of the ferry's velocity relative to the water?

Explanation:

Given

Velocity of Passenger w.r.t to Ferry

-------1

Velocity of Passenger w.r.t to water

--------2

Subtract 2 from 1

(b)direction

North of west

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s