Two pianos each sound the same note simultaneously, but they are both out of tune. on a day when the speed of sound is 349 m/s, piano a produces a wavelength of 0.766 m, while piano b produces a wavelength of 0.776 m. how much time separates successive beats?

Time period between the successive beats will be 0.1703 sec

Explanation:

We have given speed of the sound v = 349 m/sec

Wavelength of piano

Wavelength of piano  

So frequency of piano A

Frequency of piano B

So beat frequency f = 455.61 - 449.74 = 5.87 Hz

So time period

So time period between the successive beats will be 0.1703 sec

i would think form in reponse to tensional forces

d.7.5cm is your answer