Ask your teacher a cylinder is closed by a piston connected to a spring of constant 2.40 103 n/m. with the spring relaxed, the cylinder is filled with 5.00 l of gas at a pressure of 1.00 atm and a temperature of 20.0°c. (a) if the piston has a cross-sectional area of 0.0110 m2 and negligible mass, how high will it rise when the temperature is raised to 250°c? m (b) what is the pressure of the gas at 250°c?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Idk just need points

Inelastic is the answer your looking for.